Quetion : A weather balloon is inflated to a volume of 27.9L at a pressure of 732 mmHg and a temperature of 30.1°C. The balloon rises in the atmosphere to an altitude where the pressure is 385 mmHg and the temperature is -13.6°C.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
Answer:
Given -
Initial volume, V1 = 27.9 L
Initial pressure, P1 = 732 mmHg
Initial temperature, T1 = 30.1 °C => 303.1 K
Final pressure, P2 = 385 mmHg
Final temperature, T2 = -13.6°C => 259.4 K
Final Volume, V2 = ? L
According to the Combined gas Law:
(P1V1) / (T1) = (P2V2) /(T2) ......(A)
Now, put all the values in equation (A), we get
(732mmHg × 27.9L) /(303.1K) = (385 mmHg × V2) / (259.4 K)
V2 = [(732mmHg × 27.9L) × (259.4K)] / [(303.1K × 385 mmHg)]
V2 = 5297674.32 / (116693.5)
V2 = 45.399 L
V2 = 45.40 L
The volume of the balloon at this altitude is 45.40 L